The triangular wedge shown in Figure 2 resides in air moving at M = 3. Making...
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The triangular wedge shown in Figure 2 resides in air moving at M₁ = 3. Making the assump- tions that (1) the flow separates at the corners, with the streamlines trailing downstream of the corners deflected toward the base at an angle of 15 degrees from the horizontal and (2) the base pressure PB is the arithmetic average between the pressure downstream of the expansion waves, and the free-stream pressure P₁. Pdownstream + P₁₂ 2 PB Find the drag coefficient of the triangular wedge. M₁ 15° (Pg Figure 2: Triangular wedge in supersonic flow 15° 15° The triangular wedge shown in Figure 2 resides in air moving at M₁ = 3. Making the assump- tions that (1) the flow separates at the corners, with the streamlines trailing downstream of the corners deflected toward the base at an angle of 15 degrees from the horizontal and (2) the base pressure PB is the arithmetic average between the pressure downstream of the expansion waves, and the free-stream pressure P₁. Pdownstream + P₁₂ 2 PB Find the drag coefficient of the triangular wedge. M₁ 15° (Pg Figure 2: Triangular wedge in supersonic flow 15° 15°
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Solutions Step 1 The drag coefficient of the triangular wedge is 1 This can be found by analyzing th... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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