following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02...

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following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415 following summary statistics: # of Students Mean Standard Deviation Section A01 10 64.6 20.20 Section A02 8. 71.0 11.27 Question 8 (1 point) V Saved A 99% confidence interval for the difference in the true mean midterm scores of Section A01 and A02 students is calculated. Which of the following provides a correct interpretation of this interval? Approximately 99% of samples of 10 students from A01 and 8 students from A02 will have a difference in midterm scores between the endpoints of the calculated confidence interval. O In repeated samples of 10 A01 students and 8 A02 students, 99% of similarly constructed intervals will contain the difference in sample mean midterm scores. O In repeated samples of 10 A01 students and 8 A02 students. 99% of similarly constructed intervals will contain the difference in true mean midterm scores of A01 students and A02 students. The probability that u, - u lies in the calculated interval is 0.99. Question 9 (1 point) Saved We would like to conduct a hypothesis test to determine whether the true mean midterm score for Section A02 students is higher than the true mean midterm score for Section A01 students. What are the hypotheses for the appropriate test of significance? Ho: X Vs. H.: X A02 > X , A02 A01 A01 Ho HA02 = HA01 VS. Ha:HA02 = HA01 VS. Ha: µ A02>HA01 O Ho HA02 = HA01 VS. Ha: µ A02#H A01 OHo: X Но : A01 vs. Ha: X A027 A A01 A02 Question 10 (1 point) V Saved Refer to the previous question. Using the critical value method of hypothesis testing, with a 10% level of significance, we would reject Ho if: Ot2 1.746 orts-1.746 t 1.895 or t s-1.895 Otz 1.895 Otz 1.415 Otz 1.746 Otz 1.337 Otz 1.337 or ts-1.337 Otz 1.415 or ts-1.415