Three resistances are in series to a source of 40 V. The total current is 0.2A
R1 = (x^2-301) OHMS
R2 = (x-1) OHMS
R3 = (3x-23) OHMS

Question:
What are the values of E1 and E2?

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Answer the following questions. Solve for the unknown given the problem. NOTE: Acceptable units are: A, V, OHMS, WATTS, WATTHOUR. Make sure to write it in all capital letters. Answer should be in this form NUMBER space UNIT (Examples of accepted answers: 27 OHMS, 5 V, 2 A; Examples of not accepted answers are 270HMS, 27ohms, 27 ohms, 5 volts, 5volts, 5VOLTS, 5V, 2amp, 2amps, 2 amp, 2 amps, 2Watt, 2Wattshour, 2 watthr, etc.) PROBLEMS: 1. When two resistances R1 and R2 are in series, the total resistance is 576 OHMS. When connected in parallel, the total resistance becomes 44 OHMS. Note: R1 is greater than R2. 2. Three resistances are in series to a source of 40 V. The total current is 0.2 A. R1 = (x^2-301) OHMS R2 = (x - 1) OHMS R3 = (3x-23) OHMS The value of E2 in problem number 2. Your answer The value of E1 in problem number 2. Your answer Answer the following questions. Solve for the unknown given the problem. NOTE: Acceptable units are: A, V, OHMS, WATTS, WATTHOUR. Make sure to write it in all capital letters. Answer should be in this form NUMBER space UNIT (Examples of accepted answers: 27 OHMS, 5 V, 2 A; Examples of not accepted answers are 270HMS, 27ohms, 27 ohms, 5 volts, 5volts, 5VOLTS, 5V, 2amp, 2amps, 2 amp, 2 amps, 2Watt, 2Wattshour, 2 watthr, etc.) PROBLEMS: 1. When two resistances R1 and R2 are in series, the total resistance is 576 OHMS. When connected in parallel, the total resistance becomes 44 OHMS. Note: R1 is greater than R2. 2. Three resistances are in series to a source of 40 V. The total current is 0.2 A. R1 = (x^2-301) OHMS R2 = (x - 1) OHMS R3 = (3x-23) OHMS The value of E2 in problem number 2. Your answer The value of E1 in problem number 2. Your answer

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