Use the method of characteristics to solve the following first order partial differential equations: 1. Ux+uy=2x+2y,...

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Use the method of characteristics to solve the following first order partial differential equations: 1. Ux+uy=2x+2y, u(x,0)=x² 2. Us+uyu, u(x,0) = 1+e 3. u,+yu=0, u(0,y) = 1 4.3ux-2uy=3sinx, 5. U+U=2u, u(x,0) = e 6. xu+u =2u, u(x,0) = x 7. us+yuy=2u, u(0,y) = y 8. +My sinhx+sinhy, u(0,y) = 1+coshy 9. us+y=2x+2y, u(x,0)=0 u(0,y)=3y-1 Use the method of characteristics to solve the following first order partial differential equations: 1. Ux+uy=2x+2y, u(x,0)=x² 2. Us+uyu, u(x,0) = 1+e 3. u,+yu=0, u(0,y) = 1 4.3ux-2uy=3sinx, 5. U+U=2u, u(x,0) = e 6. xu+u =2u, u(x,0) = x 7. us+yuy=2u, u(0,y) = y 8. +My sinhx+sinhy, u(0,y) = 1+coshy 9. us+y=2x+2y, u(x,0)=0 u(0,y)=3y-1

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Sure here are the solutions to the given firstorder partial differential equations using the method of characteristics 1 usy2x2y ux 0 x The characteristic equations are dxds 2 and dyds 1 Solving these ... View the full answer