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Using DeMorgan's theorem, show that: a. (A + B)'(A + B)-0 b. A + A'B + A'B' = 1

Using DeMorgan's theorem, show that: a. (A + B)'(A' + B) - 0 b. A + A'B + A'B' = 1 

Using DeMorgan's theorem, show that: a. (A + B)'(A + B)-0 b. A + A'B + A'B' = 1

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