Using that limx0 sin x X = sin x 1. limx2 X 1. lim 0 1....

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Using that limx0 sin x X = sin x 1. limx2 X 1. lim 0 1. lim 0 Xx 1, compute the following limits: 1. limx0 1. limx0 1. limx0 sin(5x) tan (2x) x4 sin ex ex 1-cos x X 10 tan 0 (2x0) 200 sin (3x) 1. limx0 [(sin x) (cos(2x)) (tan(3x)) (sec(4x)) (csc(5x)) (cot (6x))] Using that limx0 sin x X = sin x 1. limx2 X 1. lim 0 1. lim 0 Xx 1, compute the following limits: 1. limx0 1. limx0 1. limx0 sin(5x) tan (2x) x4 sin ex ex 1-cos x X 10 tan 0 (2x0) 200 sin (3x) 1. limx0 [(sin x) (cos(2x)) (tan(3x)) (sec(4x)) (csc(5x)) (cot (6x))]

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The image youve provided has a list of limits that are to be computed using the standard trigonometric limit limx to 0 fracsinxx 1 Lets compute these limits one by one 1 limx to 2 fracsinxx Since the ... View the full answer