We observe the trait of face freckles (F/f) within a population of 800 people in Mesa....

   

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We observe the trait of face freckles (F/f) within a population of 800 people in Mesa. For this assignment, assume freckles on the face are a heritable trait and are controlled by one gene, where freckles are dominant (F) over non-freckled (f). The distribution of genotypes within this population are shown below in Table 1. Table 1: Freckles genotype distribution of Tempe population Genotype Number of individuals FF 257 Ff ff Total (N) 438 105 800 1. Calculate the allele frequencies and the expected genotype frequencies. (Show your calculations and round to 3 decimal places). a. Allele frequencies: (1 pt: 0.5 pts per frequency) (F)-p=2(F)+Ff f(f)-q- 2(N) Expected genotype frequencies: (1.5 pts: 0.5 pts per frequency) p = q = 2pq = 2. Complete the next table calculating the expected number of individuals for each genotype (round to the nearest whole number) and then the Chi-square statistic (X) using the equation below (round to the 3 decimal places). Show your calculations. (2 pts total: 0.25/box) Observed Expected (Round to the nearest whole #) FF Ff 257 438 x (Round to the 3rd (Obs - Exp)/Exp= decimal) 2pq*N= x Total (N) 800 800 3. Based on your x2 calculations, circle or bold the sentence that states the conclusion for your hypothesis test, assuming a P-value of 0.05 using the chi-square distribution table. (0.5 pt) We failed to reject the null hypothesis that states that the alleles (F/f) that code for face freckles are in Hardy-Weinberg equilibrium in this population. We reject the null hypothesis that states that the alleles (F/f) that code for face freckles are in Hardy-Weinberg equilibrium in this population. Degrees of Percentage Points of the Chi-Square Distribution Alpha Probability of a larger value of x2 Freedom 0.99 0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01 1 0.000 0.004 0.016 0.102 0.455 1.32 2.71 3.84 6.63 2 0.020 0.103 0.211 0.575 1.386 2.77 4.61 5.99 9.21 Critical 3 0.115 0.352 0.584 1.212 2.366 4.11 6.25 7.81 11.34 4 0.297 0.711 1.064 1.923 3.357 5.39 7.78 9.49 13.28 value 5 0.554 1.145 1.610 2.675 4.351 6.63 9.24 11.07 15.09 We observe the trait of face freckles (F/f) within a population of 800 people in Mesa. For this assignment, assume freckles on the face are a heritable trait and are controlled by one gene, where freckles are dominant (F) over non-freckled (f). The distribution of genotypes within this population are shown below in Table 1. Table 1: Freckles genotype distribution of Tempe population Genotype Number of individuals FF 257 Ff ff Total (N) 438 105 800 1. Calculate the allele frequencies and the expected genotype frequencies. (Show your calculations and round to 3 decimal places). a. Allele frequencies: (1 pt: 0.5 pts per frequency) (F)-p=2(F)+Ff f(f)-q- 2(N) Expected genotype frequencies: (1.5 pts: 0.5 pts per frequency) p = q = 2pq = 2. Complete the next table calculating the expected number of individuals for each genotype (round to the nearest whole number) and then the Chi-square statistic (X) using the equation below (round to the 3 decimal places). Show your calculations. (2 pts total: 0.25/box) Observed Expected (Round to the nearest whole #) FF Ff 257 438 x (Round to the 3rd (Obs - Exp)/Exp= decimal) 2pq*N= x Total (N) 800 800 3. Based on your x2 calculations, circle or bold the sentence that states the conclusion for your hypothesis test, assuming a P-value of 0.05 using the chi-square distribution table. (0.5 pt) We failed to reject the null hypothesis that states that the alleles (F/f) that code for face freckles are in Hardy-Weinberg equilibrium in this population. We reject the null hypothesis that states that the alleles (F/f) that code for face freckles are in Hardy-Weinberg equilibrium in this population. Degrees of Percentage Points of the Chi-Square Distribution Alpha Probability of a larger value of x2 Freedom 0.99 0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01 1 0.000 0.004 0.016 0.102 0.455 1.32 2.71 3.84 6.63 2 0.020 0.103 0.211 0.575 1.386 2.77 4.61 5.99 9.21 Critical 3 0.115 0.352 0.584 1.212 2.366 4.11 6.25 7.81 11.34 4 0.297 0.711 1.064 1.923 3.357 5.39 7.78 9.49 13.28 value 5 0.554 1.145 1.610 2.675 4.351 6.63 9.24 11.07 15.09