What is the free Cu$2+$ concentration if $0\mathrm{.}020$ M Cu$2+$ solution is mixed with an equal volume of $4\mathrm{.}0$ M NH$3?$ Kf for $[$Cu$($NH$3)4]2+$ is $1\mathrm{.}1\backslash$times $1013.$

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To find the concentration of free Cu ions you can use the concept of complex form... View the full answer