What is the runtime of the following code? Show your work (justify your answer). 1 void...

 

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What is the runtime of the following code? Show your work (justify your answer). 1 void magic(char *str1, char *str2) { 2- 234565 7 for (int i = 0; str1[i] != '\0'; ++i) { int length = strlen(str2); for (int j = 0; j < length; if (str1[i] == str2[j]) { = '* ' ; str2[j] } 8 } 9 printf("%s ", str2); 10 } 11} +j) { What is the runtime of the following code? Show your work (justify your answer). 1 void magic(char *str1, char *str2) { 2- 234565 7 for (int i = 0; str1[i] != '\0'; ++i) { int length = strlen(str2); for (int j = 0; j < length; if (str1[i] == str2[j]) { = '* ' ; str2[j] } 8 } 9 printf("%s ", str2); 10 } 11} +j) {

Answer rating: 100% (QA)

To determine the runtime of the given code we need to analyze the number of operations performed Let... View the full answer