When a new 9.0 V battery is connect to a torch, the power emitted by the bulb is 6.0 W. After the battery has run-down somewhat, the internal resistance of the run-down battery is 7.4 . What is the power emitted by the bulb now? (You should assume that the resistance of the bulb is independent of the current flowing through it.)

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To solve this problem we can use the concept of a simple circuit with a battery a bulb which represe... View the full answer