When will the rock hit the surface? We note that the rock will hit the surface...

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When will the rock hit the surface? We note that the rock will hit the surface when its height above the surface is 0 m. We previously defined the position function as f(t) = 16t - 1.86t2, where t is measured in seconds and fis measured in meters per second. Setting f(t) equal to 0 and solving for t gives us the exact time t at which the rock hits the surface. 16t 1.86t² = 0 We note that solving for t gives two results. One solution is t = 0. Give the other solution without rounding the result. t = We note that the solution t = 0 can be ignored here because that is the time just as the rock is thrown. Since we wish to determine the time when it later hits the ground, the second solution is the one we are interested in. Recalling that t is measured in seconds, we can state when (in seconds) the rock will hit the surface. (Round your result to one decimal place.) When will the rock hit the surface? We note that the rock will hit the surface when its height above the surface is 0 m. We previously defined the position function as f(t) = 16t - 1.86t2, where t is measured in seconds and fis measured in meters per second. Setting f(t) equal to 0 and solving for t gives us the exact time t at which the rock hits the surface. 16t 1.86t² = 0 We note that solving for t gives two results. One solution is t = 0. Give the other solution without rounding the result. t = We note that the solution t = 0 can be ignored here because that is the time just as the rock is thrown. Since we wish to determine the time when it later hits the ground, the second solution is the one we are interested in. Recalling that t is measured in seconds, we can state when (in seconds) the rock will hit the surface. (Round your result to one decimal place.)

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Solution The given function is ... View the full answer