Why does 10000W represents pt? The SI unit of momentum is not wats, so I don't understand.
 

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A 500 kg roller-coaster cart (including the riders in it) is pulled to the top of the first 23.76- Parallel to inclined m-high hill using a mechanical winch (assume this to be "tension" pulling up the cart). The fath continuous constant power supplied by the winch to pull the cart up at a constant speed of 2.0 m/s is 10000 W. Some energy leaves the system as thermal energy during this climb. (14 marks) roller coaster cart A 23.76 m 70° Once at the top of the hill with a speed of 2.0 m/s, the cart descends on a frictionless rail until the bottom where the wheels lock, and friction acts on the wheels for some distance in order to stop the cart safely. The kinetic friction coefficient at the bottom (flat portion) of the roller coaster between the surface and the locked wheels is 0.4. (6.5) First, assess Work by mechanical winch] motor (or "feasion') W4=? conte Cart a) How much work is done by friction during the initial climb of the cart? P (note: F: {600 = 2 10000 W F =P / V P-F+ • V = F₂U (0) F₁) (botton = 5000 N W-F4XF 4x Cos (0) 5000 (2376) 126424 J 20 Note that akik mash 500 (4.8) (23.76) 116 424 J bottom-yop ZW₁ E₂ E₁ to Ⓒ) Wf & We = AK + aUg 4K 126424 +W₁0 + 116424 WE 7-10000 J los We 10000 A 500 kg roller-coaster cart (including the riders in it) is pulled to the top of the first 23.76- Parallel to inclined m-high hill using a mechanical winch (assume this to be "tension" pulling up the cart). The fath continuous constant power supplied by the winch to pull the cart up at a constant speed of 2.0 m/s is 10000 W. Some energy leaves the system as thermal energy during this climb. (14 marks) roller coaster cart A 23.76 m 70° Once at the top of the hill with a speed of 2.0 m/s, the cart descends on a frictionless rail until the bottom where the wheels lock, and friction acts on the wheels for some distance in order to stop the cart safely. The kinetic friction coefficient at the bottom (flat portion) of the roller coaster between the surface and the locked wheels is 0.4. (6.5) First, assess Work by mechanical winch] motor (or "feasion') W4=? conte Cart a) How much work is done by friction during the initial climb of the cart? P (note: F: {600 = 2 10000 W F =P / V P-F+ • V = F₂U (0) F₁) (botton = 5000 N W-F4XF 4x Cos (0) 5000 (2376) 126424 J 20 Note that akik mash 500 (4.8) (23.76) 116 424 J bottom-yop ZW₁ E₂ E₁ to Ⓒ) Wf & We = AK + aUg 4K 126424 +W₁0 + 116424 WE 7-10000 J los We 10000