Write function called fancy_find. fancy_find should have
#two parameters: search_within and search_for.
#
#fancy_find should check if search_for is found within the
#string search_within. If it is, it should print the message
#"[search_for] found at index [index]!", with [search_for]
#and [index] replaced by the value of search_for and the
#index at which it is found. If search_for is not found
#within search_within, it should print, "[search_for] was
#not found within [search_within]!", again with the values
#of search_for and search_within.
#
#For example:
#
#  fancy_find("ABCDEF", "DEF") -> "DEF found at index 3!"
#  fancy_find("ABCDEF", "GHI") -> "GHI was not found within ABCDEF!"

#Add function here!
def fancy_find(search_within, search_for):
   index = search_within.index(search_for)

   if search_for in search_within:
       return (search_for, "found at index", index)
   else:
       return (search_for, "was not found within", search_within, "!")

#Below are some lines of code that will test your function.
#You can change the value of the variable(s) to test your
#function with different inputs.
#
#If your function works correctly, this will originally
#print:
#DEF found at index 3!
#GHI was not found within ABCDEF!

print(fancy_find("ABCDEF", "DEF"))
print(fancy_find("ABCDEF", "GHI"))

 

'''''

The feedback:

('DEF', 'found at index', 3)
Traceback (most recent call last):
  File "FancyFind.py", line 38, in
    print(fancy_find("ABCDEF", "GHI"))
  File "FancyFind.py", line 21, in fancy_find
    index = search_within.index(search_for)
ValueError: substring not found
Command exited with non-zero status 1

 

 

 

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It should print out:

fancy_find("ABCDEF", "DEF") -> "DEF found at index 3!"
fancy_find("ABCDEF", "GHI") -> "GHI was not found within ABCDEF!"

 

 

 

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where i need help, I can't get help to print:

"GHI was not found within ABCDEF!"

Answer rating: 100% (QA)

The issue with your code is that youre trying to access the ind... View the full answer