You launch a projectile toward a tall building, from a position on the ground 25.3$\mathrm{}\mathrm{}\mathrm{}\mathrm{}$ m away from the base of the building. The projectile s initial velocity is 33.5$\mathrm{}\mathrm{}\mathrm{}\mathrm{}$ m/$/$s at an angle of 54.5$\mathrm{}\mathrm{}\mathrm{}\mathrm{}$ degrees above the horizontal. At what height above the ground does the projectile strike the building? 

 

 You launch a projectile horizontally from a building $21\mathrm{.}7$ m above the ground at another building $45\mathrm{.}8$ m away from the first building. The projectile strikes the second building $2\mathrm{.}4$ m above the ground. What was the projectile s launch speed? 

 

 

 

  

 

Answer rating: 100% (QA)

For the first question we can use the equations of motion to find the height above the ground where ... View the full answer