In Fig 3 22, the two boxes have identical masses of 40 kg Both experience a sliding friction force with k 0 15 Find the acceleration of the boxes and the tension in the tie cord FEA FNA 15 WA 1 A Fr mg cos 30 30 Fig 3 22 NB mg sin 30 B 30...

Using F HkFN the friction forces on the two boxes are N FfA 015mg and FfB 0150866 mg But m ...

In Fig. 3-22, the two boxes have identical masses of 40 kg. Both experience a sliding friction

Question:

In Fig. 3-22, the two boxes have identical masses of 40 kg. Both experience a sliding friction force with μ_k = = 0.15. Find the acceleration of the boxes and the tension in the tie cord. FEA FNA 15= WA 1 A Fr mg cos 30 30 Fig. 3-22 NB + mg sin 30 B 30