When n = 1 in Eq. (43.9), we get the radius of the lowest energy orbit (the

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When n = 1 in Eq. (43.9), we get the radius of the lowest energy orbit (the ground state orbit) called the Bohr radius. Numerically that’s.

Using Eq. (43.9), show that the diameter of a hydrogen atom is just about 0.10 nm, thereby confirming Eq. (43.10) to four significant figures.

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Schaums Outline Of College Physics

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Authors: Eugene Hecht

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Question Posted: Nov 04, 2023 09:48 PM

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When n = 1 in Eq. (43.9), we get the radius of the lowest energy orbit (the

Question:

r₁ = 0.0529177 nm (43.10)

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Schaums Outline Of College Physics

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