Given the two realizations in Figure 6.27 obtain the corresponding transfer functions Figure 6.27: Y1 (s)
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Figure 6.27:
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Y1 (s) Н () %— X1 (s) Y,(s) -, and H2(s) X,(s) Realization 1 y1 (t) v1(t) v2(t) r1(t) Realization 2 x2(t) w2(t) wi(t) 42(t) 2) 2.
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For the realization 1 we have the following equations y 1 t v 1 t 2v 2 t v 1 t x 1 t v 1 t 2v ...View the full answer
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