The output of an ideal low-pass filter is (a) Assume the filter input is a periodic signal
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(a) Assume the filter input is a periodic signal x[n]. What is its fundamental frequency Ï0? What is the fundamental period N0?
(b) When the filter is low-pass with H(ej0) = H(ejÏ0) = H(ejÏ0) = 1 and H(ej2Ï0) = H(ej2Ï0) = 1/2 determine the Fourier series for the input x[n].
Transcribed Image Text:
y[n] = 1+(2/k) cos(0.2t kn) 0 < n < ∞. k=1 |
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a If xn is periodic of fundamental period N 0 its DTFT is then the DTFT of the output would be ...View the full answer
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