Consider a random variable (X) in the family of Poisson distributions with parameter (lambda). As (lambda) varies

Question:

Consider a random variable \(X\) in the family of Poisson distributions with parameter \(\lambda\). As \(\lambda\) varies from 1 to 9 , both the mean and the variance of \(X\) increase from 1 to 9 . Now consider the transformation \(Y=\log (X+1)\). How do the mean and variance of \(Y\) vary as \(\lambda\) varies from 1 to 9 ?

Simulate 1,000 realizations of \(X\) for each \(\lambda \in\{1,2, \ldots, 9\}\), and for each value of \(\lambda\), compute the sample mean and variance of your simulated sample. How do the mean and variance vary?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: