If the standard deviation () associated with the pdf that produced the following sample is 3.6, would
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If the standard deviation (σ) associated with the pdf that produced the following sample is 3.6, would it be correct to claim that
is a 95% confidence interval for μ? Explain.
Transcribed Image Text:
3.6 √20 2.611.96- 2.61 + 1.96. 3.6 √20 = (1.03, 4.19)
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