Show that the mean of a hypergeometric random variable Y is = nr/N. Show that and
Question:
Show that the mean of a hypergeometric random variable Y is μ = nr/N. Show that
and then use the fact that
is the hypergeometric probability distribution for Z = (Y - 1), where Z is the number of S’s in (n - 1) trials, with a total of (r - 1) S’s in (N - 1) elements.]
Transcribed Image Text:
(N 1-(r-1)) - 1- (у — 1)/ nr N N. N-
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To show that the mean of a hypergeometric random variable Y is nrN we can use the definition of the mean for a discrete random variable The hypergeome...View the full answer
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Related Book For
Statistics For Engineering And The Sciences
ISBN: 9781498728850
6th Edition
Authors: William M. Mendenhall, Terry L. Sincich
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