For a Poisson distribution [p(k, lambda)=frac{lambda^{k}}{k !} e^{-lambda}] find (a) (p(2,1)), (b) (pleft(3, frac{1}{2}ight)), and (c) (p(2,7)).

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For a Poisson distribution

\[p(k, \lambda)=\frac{\lambda^{k}}{k !} e^{-\lambda}\]

find

(a) \(p(2,1)\),

(b) \(p\left(3, \frac{1}{2}ight)\), and

(c) \(p(2,7)\).

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