For a Poisson distribution [p(k, lambda)=frac{lambda^{k}}{k !} e^{-lambda}] find (a) (p(2,1)), (b) (pleft(3, frac{1}{2}ight)), and (c) (p(2,7)).
Question:
For a Poisson distribution
\[p(k, \lambda)=\frac{\lambda^{k}}{k !} e^{-\lambda}\]
find
(a) \(p(2,1)\),
(b) \(p\left(3, \frac{1}{2}ight)\), and
(c) \(p(2,7)\).
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