The circuit in Figure P11.91 has two bipolar differential amplifiers in cascade, biased with ideal current sources \(I_{Q 1}\) and \(I_{Q 2}\). Assume the transistor parameters are \(\beta=180\) and \(V_{A}=\infty\).

(a) Design the circuit such that \(v_{o 1}=v_{o 2}=2 \mathrm{~V}\) and \(v_{O 4}=6 \mathrm{~V}\) when \(v_{1}=v_{2}=0\).

(b) Determine the differential-mode voltage gains \(A_{d 1}=\left(v_{o 1}-v_{o 2}\right) / v_{d}\) and \(A_{d}=v_{o 4} / v_{d}\).

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www RC V+= 10 V ww RC\ Vol 029 Q2 ww RC2 Rc2 Q4 401 = 0.2 mA +402 = 0.4 mA V-=-10 V Figure P11.91 V-=-10 V