For a single-phase, two-wire line consisting of two solid cylindrical conductors of same radius, (r), the total

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For a single-phase, two-wire line consisting of two solid cylindrical conductors of same radius, \(r\), the total circuit inductance, also called loop inductance, is given by (in \(\mathrm{H} / \mathrm{m}\) )

(a) \(2 \times 10^{-7} \ln \left(\frac{\mathrm{D}}{r^{\prime}}ight)\)

(b) \(4 \times 10^{-7} \ln \left(\frac{\mathrm{D}}{r^{\prime}}ight)\)

where \(r^{\prime}=e^{-\frac{1}{4}} r=0.778 r\)

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Related Book For  answer-question

Power System Analysis And Design

ISBN: 9781305632134

6th Edition

Authors: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

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