Derive eq. (30.15) by equating the normal force per unit length on a blade element given in
Question:
Derive eq. (30.15)
by equating the normal force per unit length on a blade element given in eq. (30.12)
with the thrust per unit length obtained from the axial momentum analysis (30.14)
.
Transcribed Image Text:
8πα K sin o Àc B pOK Bu2(1 – a)²c ST =-K Bu q sino 2 2, 2 sin o oK Bu²(1 – a)²cj cos o SN=;P0K Bw²cj cos o f =- ø î: 2 sin?
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