Steam enters the nozzle of a turbine with a velocity of 3 m/s at a pressure of
Question:
Steam enters the nozzle of a turbine with a velocity of 3 m/s at a pressure of 35 bar and a temperature of 800 K. At the exit of the nozzle the pressure and temperature are found to be 1 bar and 400 K. Calculate the velocity at the exit of the nozzle and the entropy-production rate for the control volume enclosing the nozzle if the mass flow rate is 4500 kg/hr. Use Appendix A.3 for data.
Data From A.3
Transcribed Image Text:
SIV / T/ piat / v/ $ 1 UV/ H/h™V / h / K MPa m³/kg m³/kg kJ/kg kJ/kg kJ/kg kJ/(kg K) kJ/(kg K) kJ/(kg .K) 273.16 0.0006117 0.001000 206.0 0.0 2500.9 2500.9 0.0 9.1555 9.1555 275 0.0006985 0.001000 181.6 7.8 280 0.0009918 0.001000 130.2 28.8 285 0.001389 0.001001 94.61 290 0.001920 295 0.002621 300 0.003537 305 0.004719 310 0.006231 0.008145 315 320 0.01055 325 0.01 353 330 0.01721 335 0.02172 340 0.02719 345 0.03378 350 0.04168 355 0.05 108 360 0.06219 365 0.07526 370 0.09054 375 0.1083 380 0.1289 385 0.1525 390 0.1796 395 0.2106 400 0.2458 405 0.2856 2496.5 2504.3 0.0283 9.0783 2484.7 2513.5 0.1041 8.8738 2472.8 2522.6 0.1784 49.8 70.7 2461.0 2531.7 0.2513 0.001001 69.63 0.001002 51.87 91.7 2449.2 2540.8 0.3228 0.001003 39.08 112.6 2437.3 2549.9 0.3931 0.001005 29.77 133.5 2425.4 2558.9 0.4622 0.001007 22.91 154.4 2413.5 2567.9 0.5302 0.001009 17.80 175.3 2401.6 2576.8 0.5970 196.2 2389.6 2585.7 0.6629 0.001011 13.96 0.001013 11.04 217.1 2377.5 2594.6 0.7277 0.001015 8.806 238.0 2365.4 2603.3 0.7915 0.001018 7.079 258.9 0.001021 5.734 279.8 2353.2 2612.1 0.8544 2340.9 2620.7 0.9164 8.6766 8.4862 8.3023 8.1244 7.9523 7.7856 7.6241 7.4674 7.3154 7.1678 7.0244 6.8849 6.7492 6.6171 0.001024 4.678 300.8 2328.5 2629.3 0.9775 2316.0 2637.7 1.0378 0.001027 3.842 321.7 0.001030 3.176 342.7 2303.4 2646.1 1.0973 0.001034 2.642 363.7 2290.7 2654.4 1.1560 0.001037 2.210 0.001041 1.859 384.8 2277.8 2662.5 1.2140 405.8 2264.8 2670.6 1.2713 0.001045 1.572 426.9 2251.6 2678.5 1.3279 0.001049 1.336 448.0 2238.2 2686.3 1.3838 0.001053 1.141 469.2 2224.7 2693.9 1.4390 6.0042 5.8900 5.7783 0.001058 0.9794 490.4 2210.9 2701.3 1.4937 5.6690 0.001062 0.8440 511.7 2197.0 2708.6 1.5477 5.5619 0.001067 0.7303 532.9 2182.8 2715.7 1.6012 0.001072 0.6345 554.3 2168.3 2722.6 1.6542 6.4884 6.3629 6.2405 6. 1209 5.4569 5.3539 9.1066 8.9779 8.8550 8.7375 8.6251 8.5175 8.4145 8.3158 8.2211 8.1303 8.0431 7.9593 7.8787 7.8013 7.7267 7.6549 7.5857 7.5189 7.4545 7.3922 7.3320 7.2738 7.2174 7.1627 7.1096 7.0581 7.0080
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To solve this problem we can use the conservation of mass and energy equations for steadyflow system...View the full answer
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Related Book For
Thermodynamics Fundamentals And Engineering Applications
ISBN: 9780521862738
1st Edition
Authors: William C. Reynolds, Piero Colonna
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