A small block with mass 0 0400 kg is moving in the xy plane The net force on the block is described by the potential energy function U(x, y) (5 80 J m 2 )x 2 (3 60 J m 3 )y 3 What are the magnitude and direction of the acceleration of the block when it is at the point (x 0 300 m, y 0 600 m) ...

IDENTIFY From the potential energy function of the block we can find the ...

A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the

Question:

A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential energy function U(x, y) = (5.80 J/m²)x² - (3.60 J/m³)y³. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.300 m, y = 0.600 m)?

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