An alpha particle with kinetic energy 9.50 MeV (when far away) collides headon with a lead nucleus
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An alpha particle with kinetic energy 9.50 MeV (when far away) collides headon with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)
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Related Book For
University Physics with Modern Physics
ISBN: 978-0133977981
14th edition
Authors: Hugh D. Young, Roger A. Freedman
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