Equation (31.9) says that v ab = L di/dt (see Fig. 31.8a). Using Faradays law, explain why

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Equation (31.9) says that vab= L di/dt (see Fig. 31.8a). Using Faraday€™s law, explain why point a is at higher potential than point b when i is in the direction shown in Fig. 31.8a and is increasing in magnitude. When i is counterclockwise and decreasing in magnitude, is vab= L di/dt still correct, or should it be vab= -L di/dt? Is vab= L di/dt still correct when i is clockwise and increasing or decreasing in magnitude? Explain.


Fig.31.8

i k-UL-

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University Physics with Modern Physics

ISBN: 978-0133977981

14th edition

Authors: Hugh D. Young, Roger A. Freedman

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