When two point charges of equal mass and charge are released on a frictionless table, each has an initial acceleration (magnitude) a 0 If instead you keep one fixed and release the other one, what will be its initial acceleration a 0 , 2a 0 , or a 0 2 Explain ...

The acceleration of the charge depends on the electric force ex ...

When two point charges of equal mass and charge are released on a frictionless table, each has

Question:

When two point charges of equal mass and charge are released on a frictionless table, each has an initial acceleration (magnitude) a₀. If instead you keep one fixed and release the other one, what will be its initial acceleration: a₀ , 2a₀ , or a₀/2? Explain.

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