Suppose that the concentrations of NaF and KCl were each 0.10 M in the cell (a) Using
Question:
(a) Using the half-reactions 2AgCI(s) + 2e- 2A , calculate the cell voltage.
(b) By the reasoning in Figure 13-8, in which direction do electrons flow?
(c) Now calculate the cell voltage by using the reactions and . For this part, you will need the solubility products for PbF2 and AgCl.
Transcribed Image Text:
Pb(s) PbF2(s)F (a)|CI (aq)AgCI(s)lAg(s)
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a E E F 0281 2 0290 8 0572 V b Electrons flow from the left halfcell E 0290s V to th...View the full answer
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