Suppose that the golf ball is launched with a speed of 15.0 m/s at an angle of
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Suppose that the golf ball is launched with a speed of 15.0 m/s at an angle of 57.5° above the horizontal, and that it lands on a green 3.50 m above the level where it was struck.
(a) What horizontal distance does the ball cover during its flight?
(b) What increase in initial speed would be needed to increase the horizontal distance in part (a) by 7.50 m? Assume everything else remains the same.
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Use the horizontal component of the initial velocity to find an expression for the time ...View the full answer
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