Question

The average income in Connecticut in 2013 was $60,000 per person per year. Suppose the standard deviation is $30,000 and the distribution is right-skewed. Suppose we take a random sample of 400 residents of Connecticut. We want to find the probability that the sample mean will be more than $3000 away from the population mean. The TI-84 output is shown.
a. Why is the distribution Normal and not right-skewed like the population?
b. Why is the z-score 2?
c. What is the probability that the sample mean will be more than $3000 away from the population mean?


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  • CreatedJuly 16, 2015
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