The electrical power P drawn from a generator by a light bulb of resistance R is P

Question:

The electrical power P drawn from a generator by a light bulb of resistance R is P = V2/R, where V is the line voltage. The resistance of bulb B is 42% greater than the resistance of bulb A. What is the ratio PB/PA of the power drawn by bulb B to the power drawn by bulb A if the line voltages are the same?
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Physics

ISBN: 978-0077339685

2nd edition

Authors: Alan Giambattista, Betty Richardson, Robert Richardson

Question Posted: