# Question: The extraction force required to remove a cork from a

The extraction force required to remove a cork from a bottle of wine has a normal distribution with a mean of 310 Newtons and a standard deviation of 36 Newtons.

a. The specs for this variable, given in Applied Example 6.13, were “300 N + 100 N/-150 N” Express these specs as an interval.

b. What percentage of the corks is expected to fall within the specs?

c. What percentage of the tested corks will have an extraction force of more than 250 Newtons?

d. What percentage of the tested corks will have an extraction force within 50 Newtons of 310?

a. The specs for this variable, given in Applied Example 6.13, were “300 N + 100 N/-150 N” Express these specs as an interval.

b. What percentage of the corks is expected to fall within the specs?

c. What percentage of the tested corks will have an extraction force of more than 250 Newtons?

d. What percentage of the tested corks will have an extraction force within 50 Newtons of 310?

**View Solution:**## Answer to relevant Questions

The diameter of each cork, as described in Applied Example 6.13, is measured in several places and an average diameter is reported for the cork. The average diameter has a normal distribution with a mean of 24.0 mm and ...Using the z(a) notation (identify the value of a used within the parentheses), name each of the standard normal variable z’s shown in the following diagrams. Use Table 4A, Appendix B, and the symmetry property of normal distributions to find the following values of z. a. z(0.05) b. z(0.01) c. z(0.025) d. z(0.975) e. z(0.98) Understanding the z notation, z(a), requires us to c. z(100 — 001) d. z (0.025) — z (0.975) know whether we have a z-score or an area. Each of the following expressions uses the z notation in a variety of ways, some ...Melanoma is the most serious form of skin cancer and is increasing at a rate higher than any other cancer in the United States. If it is caught in its early stage, the 5-year survival rate for patients on average is 98% in ...Post your question