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The health care analyst in Exercise 18 finds a 90

The health care analyst in Exercise 18 finds a 90% confidence interval for the true pro-portion of employees who fail the course to be (14.46%, 15.74%).

a) Explain why she can reject the null hypothesis that p = 0.159 vs. p < 0.159 at α = 0.05. b) Explain why the difference may or may not be important

c) Could you reject the hypothesis that p = 0.157? Explain.

a) Explain why she can reject the null hypothesis that p = 0.159 vs. p < 0.159 at α = 0.05. b) Explain why the difference may or may not be important

c) Could you reject the hypothesis that p = 0.157? Explain.

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