# Question

The infant mortality rate (IMR) is the number of infant deaths per 1000 live births. Suppose that you have been commissioned to estimate the IMR in Singapore. From a random sample of 1109 live births in Singapore, you find that 0.361% of them resulted in infant deaths. You next find a 90% confidence interval: 0.00361 ± 1.645·√(0.00361) (0.99639) / 1109, or 0.000647 to 0.00657. You then conclude, “I can be 90% confident that the IMR in Singapore is somewhere between 0.647 and 6.57.” How did you do?

## Answer to relevant Questions

An ABCNEWS Poll found that Americans now have relatively warm feelings toward Russia, a former adversary. The poll, conducted by telephone among a random sample of 1043 adults, found that 647 of those sampled consider the ...Refer to Exercise 11.28. a. Find the margin of error for the estimate of the percentage. b. Obtain a sample size that will ensure a margin of error of at most 5 percentage points for a 90% confidence interval without ...In the article “Bottled Natural Mineral Waters in Romania” (Environmental Geology Journal, Vol. 46, Issue 5, pp. 670–674), A. Feru compared the mineral, ionic, and carbon dioxide content of mineral-water source ...x = 40, n = 50, 95% level. a. Use the one-proportion plus-four z-interval procedure, as discussed on page 449, to find the required confidence interval. b. Compare your result with the corresponding confidence interval ...Repeat parts (b)–(e) of Exercise 11.5 for samples of size 1.Post your question

0