The standard enthalpy of formation of H2O(l) at 298 K is 285.8 kJ/ mol. Calculate the change

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The standard enthalpy of formation of H2O(l) at 298 K is –285.8 kJ/ mol. Calculate the change in internal energy for the following process at 298 K and 1 atm: H2O(l) → H2(g) + ½ O2(g) ΔEo = ?

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Chemical Principles

ISBN: 978-1111580650

7th edition

Authors: Steven S. Zumdahl, Donald J. DeCoste

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Question Posted: May 05, 2015 10:37 AM

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The standard enthalpy of formation of H2O(l) at 298 K is 285.8 kJ/ mol. Calculate the change

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H 2 g 12 O 2 g H 2 O l H 2858 kJ H 2 O ...View the full answer

Chemical Principles

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