The two-wattmeter method gives P1 = 1200 W and P2 = -400 W for a three-phase motor

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The two-wattmeter method gives P1 = 1200 W and P2 = -400 W for a three-phase motor running on a 240-V line. Assume that the motor load is wye-connected and that it draws a line current of 6 A. Calculate the pf of the motor and its phase impedance.

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Fundamentals Of Electric Circuits

ISBN: 9780073301150

3rd Edition

Authors: Matthew Sadiku, Charles Alexander

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Question Posted: Apr 29, 2016 03:01 PM

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The two-wattmeter method gives P1 = 1200 W and P2 = -400 W for a three-phase motor

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P T P 1 P 2 1200 400 800 Q T P ...View the full answer

Fundamentals Of Electric Circuits

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