Treatment of 2-butanone (1 mol) with Br2 (2 mol) in aqueous HBr gave C4H6Br2O. The 1H NMR

Question:

Treatment of 2-butanone (1 mol) with Br2 (2 mol) in aqueous HBr gave C4H6Br2O. The 1H NMR spectrum of the product was characterized by signals at 1.9 ppm (doublet, 3 protons), 4.6 ppm (singlet, 2 protons), and 5.2 ppm (quartet, 1 proton). Identify this compound.