Two short angle sections CE and DF are bolted to the uniform beam AB of weight 3.33kN
Question:
Two short angle sections CE and DF are bolted to the uniform beam AB of weight 3.33kN and the assembly is temporarily supported by the vertical cables EG and FH as shown. A second beam resting on beam AB at I exerts a downward force of 3 kN on AB. Knowing that a = 0.3 m and neglecting the weight of the angle sections,
(a) Raw the shear and bending-moment diagrams for beam AB,
(b) Determine the maximum absolute values of the shear and bending moment in the beam.
0.1 m -0.1m B. 1.5 m - 1.5 m
Step by Step Answer:
V KN M kNm FBD angle CE I E im Pc 3 KN 3165kN 111 kNm 12m 1833 1332 3m 15 7992 157 316...View the full answer
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