Two structures for the sugar glucose are shown on page 858. Interconversion of the open-chain and cyclic
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(a) Propose a mechanism for the cyclization, assuming a trace of acid is present.
(b) The cyclic hemiacetal is more stable than the open-chain form, so very little of the open-chain form is present at equilibrium.
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a b Yes the cyclic form of glucose will give a positive Tollens test In the basi...View the full answer
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