A uniform rod of mass M and length L is pivoted at one end and hangs as
Question:
A uniform rod of mass M and length L is pivoted at one end and hangs as in Figure so that it is free to rotate without friction about its pivot. It is struck by a horizontal force F0 for a short time Δt at a distance x below the pivot as shown.
(a) Show that the speed of the center of mass of the rod just after being struck is given by v0 = 3F0xΔt/2ML.
(b) Find the force delivered by the pivot, and show that this force is zero if x = 2L/3.
Step by Step Answer:
a The torque due to F 0 is F 0 x I ML 2 3 Thus 3 F 0 x ML 2 and t 3 F 0 x t ML 2 ...View the full answer
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
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