Use the results of Exercise 16 and Cubic Hermite interpolation to approximate values of y(t), and compare
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a. y(0.54) and y(0.94)
b. y(1.25) and y(1.93)
c. y(1.3) and y(2.93)
d. y(0.54) and y(0.94)
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Cubic Hermite interpolation gives the following results a 1...View the full answer
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