Question: Using Appendix 4 and the following data, determine So for Fe(CO)5(g). Fe(s) + 5CO(g) Fe(CO)5(g) So = ? Fe(CO)5(l) Fe(CO)5(g) So = 107
Fe(s) + 5CO(g) → Fe(CO)5(g) ΔSo = ?
Fe(CO)5(l) → Fe(CO)5(g) ΔSo = 107 J/ K
Fe(s) + 5CO(g) → Fe(CO)5(l) ΔSo = –677 J/ K
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From Appendix 4 S 198 J K 1 mol 1 for COg and S 27 J K 1 m... View full answer
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