Using bond energies from Table, estimate the barrier to rotation around a carboncarbon double bond. To do
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In terms of making and breaking chemical bonds; that is, what happens to the Ï bond?
Table 6
Transcribed Image Text:
Cl Cl Cl 0 s | 14 39 95 45 72 1 1419 6847064968 77386 42222 34 985 0302 121 Si H C O 437 490 9 31222241122 122221 25735 375859609 1 34322
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In order to rotate about the double bond the molecule must go through an intermediate ...View the full answer
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