Using Stirlings formula (see Exercise 1.6) to approximate 2n! and n!, show that 2n 22n ~ 1
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Using Stirling’s formula (see Exercise 1.6) to approximate 2n! and n!, show that
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2n 22nㅡㅡㅡ ~ 1
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Related Book For
John E Freunds Mathematical Statistics With Applications
ISBN: 9780134995373
8th Edition
Authors: Irwin Miller, Marylees Miller
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