Using the following data, calculate the standard heat of formation of ICl(g) in kJ/ mol: Cl2(g)
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Cl2(g) → 2Cl(g) ΔHo = 242.3 kJ
I2(g) → 2I(g) ΔHo = 151.0 kJ
ICl(g) → I(g) + Cl(g) ΔHo = 211.3 kJ
I2(s) → I2(g) ΔH8 = 62.8 kJ
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I g Cl g ICl g H 211 3 kJ 1 2 Cl …View the full answer
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