# Question

Using the following data, calculate the standard heat of formation of ICl(g) in kJ/ mol:

Cl2(g) → 2Cl(g) ΔHo = 242.3 kJ

I2(g) → 2I(g) ΔHo = 151.0 kJ

ICl(g) → I(g) + Cl(g) ΔHo = 211.3 kJ

I2(s) → I2(g) ΔH8 = 62.8 kJ

Cl2(g) → 2Cl(g) ΔHo = 242.3 kJ

I2(g) → 2I(g) ΔHo = 151.0 kJ

ICl(g) → I(g) + Cl(g) ΔHo = 211.3 kJ

I2(s) → I2(g) ΔH8 = 62.8 kJ

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