# Question

Using the standard normal distribution, find each probability. (6–1)

a. P (0 < z < 2.07)

b. P (–1.83 < z < 0)

c. P (–1.59 < z < + 2.01)

d. P (1.33 < z <1.88)

e. P (–2.56 < z< 0.37)

f. P (z > 1.66)

g. P(z < – 2.03)

h. P(z > –1.19)

i. P(z < 1.93)

j. P(z> – 1.77)

a. P (0 < z < 2.07)

b. P (–1.83 < z < 0)

c. P (–1.59 < z < + 2.01)

d. P (1.33 < z <1.88)

e. P (–2.56 < z< 0.37)

f. P (z > 1.66)

g. P(z < – 2.03)

h. P(z > –1.19)

i. P(z < 1.93)

j. P(z> – 1.77)

## Answer to relevant Questions

The average per capita spending on health care in the United States is $5274. If the standard deviation is $600 and the distribution of health care spending is approximately normal, what is the probability that a randomly ... A random sample of enrollments in Pennsylvania’s private four-year colleges is listed here. Check for normality. A survey of 35 individuals who passed the seven exams and obtained the rank of Fellow in the actuarial field finds the average salary to be $150,000. If the standard deviation for the population is $15,000, construct a 95% ...A health care professional wishes to estimate the birth weights of infants. How large a sample must be obtained if she desires to be 90% confident that the true mean is within 2 ounces of the sample mean? Assume σ = 8 ...Find the 90% confidence interval for the variance and standard deviation for the lifetimes of inexpensive wristwatches if a sample of 24 watches has a standard deviation of 4.8 months. Assume the variable is normally ...Post your question

0