Verify that (a) b(x; n,θ) = b(n - x; n, 1 - θ). Also show that if

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Verify that
(a) b(x; n,θ) = b(n - x; n, 1 - θ).
Also show that if B(x; n,θ)
E b(k; n,0) %3D k=0

For x = 0,1,2,€¦,n, then
(b) b(x; n,θ) = B(x; n,θ)- B(x- 1; n,θ);
(c) b(x; n,θ) = B(n- x; n, 1-θ)- B(n- x- 1; n,1- θ);
(d) B(x; n,θ) = 1 - B(n €“ x - 1; n, 1 - θ).

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